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A vessel containing liquid of density $ρ_{0}$ is moving with an acceleration $10 m / s^{2}$ in vertical x–y plane as shown, then the value of $(P_{B} - P_{A})$ is given by n $ρ_{0}$ . Find value of n. ( $P_{A} and P_{B}$ are the pressure at A and B). $(g = 10 m / s^{2})$

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answer is B.

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Detailed Solution

$(P_{B^{'} -} P_{A}) {=ρ}_{0} (g+6) 6 ..... (i) (P_{B^{'} -} P_{A}) {=ρ}_{0} (8) 8 ..... (ii)$

From (i) and (ii)

$(P_{B-} P_{A}) {=32ρ}_{0}$

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