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A vessel contains methane and oxygen in the mass ratio 1 : 1. The fraction of the partial pressure of hydrocarbon in the total pressure is

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1/4

1/3

2/3

1/2

answer is B.

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Detailed Solution

so the mole ratio of methane and oxygen = 2 : 1

According to law of partial pressure of hydrocarbon=mole fraction*total pressure

= $\frac{2}{2 + 1} = \frac{2}{3} x t o t a l p r e s s u r e$

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