A vessel has $N_{2}$ gas saturated with water vapor at a total pressure of 1 atm. The partial pressure of water vapor is $0.3 a t m .$ The contents of this vessel are completely transferred to another vessel having one third of the capacity of the original volume, at the same temperature. The total pressure of this system in the new vessel is

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$3.3 a t m$

$2.4 a t m$

$3.0 a t m$

$1 a t m$

answer is D.

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Detailed Solution

$P_{t o t a l} = P_{N_{2}} + P_{w a t e r v a p o u r} \Rightarrow P_{N_{2}} = 1 - 0.3 = 0.7 a t m$

$P_{1} V_{1} = P_{2} V_{2}, 0.7 \times V = P_{2} \times \frac{V}{3} \Rightarrow V = 2.1 a t m$

Total pressure in the new vessel $= 2.1 + 0.3 = 2.4 a t m$

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