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A vessel is filled with a mixture of oxygen and nitrogen. At what ratio of partial pressures will the mass of gases be identical ?

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$P (O_{2}) = 0 .785 P (N_{2})$

$P (O_{2}) = 8 .75 P (N_{2})$

$P (O_{2}) = 11 .4 P (N_{2})$

$P (O_{2}) = 0 .875 P (N_{2})$

answer is D.

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Detailed Solution

$PV = nRT$

$PV = \frac{w}{M} RT$

$\begin{array}{l} P_{O_{2}} V = \frac{w}{32} RT; P_{N_{2}} V = \frac{w}{28} RT \\ \frac{P_{O_{2}}}{P_{N_{2}}} = \frac{28}{32}; P_{O_{2}} = 0 .875 P_{N_{2}} \end{array}$

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