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A vessel is partly filled with liquid. When the vessel is cooled to a lower temperature, the space in the vessel unoccupied by the liquid remains constant .Then the volume of the liquid $(V_{L})$ volume of the vessel $(V_{V})$ , the coefficient of cubical expansion of the material of the vessel $(γ_{V})$ and of the liquid $(γ_{L})$ are related as

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$γ_{L} > γ_{V}$

$γ_{L} < γ_{V}$

$\frac{γ_{L}}{γ_{_{V}}} = \frac{V_{L}}{V_{V}}$

$\frac{γ_{V}}{γ_{_{L}}} = \frac{V_{L}}{V_{V}}$

answer is A, D.

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Detailed Solution

$Δ V_{L} = Δ V_{V}$

$Y_{L} V_{L} = Y_{V} V_{V} o r \frac{Y_{L}}{Y_{V}} = \frac{V_{V}}{V_{L}}$

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