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A vessel of 25 litre capacity contains 10 moles of steam under pressure of 50.3 atm. Calculate the temperature of steam using van der Waals equation (if for water a=5.46 bar L² mol^–2 and b=0.031 L mol^–1)

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1539.5 K

153.95 K

15.395 K

1.5395 K

answer is A.

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Detailed Solution

$(P + \frac{{an}^{2}}{V^{2}}) (V - nb) = nRT [50.3 + \frac{5.46 \times {(10)}^{2}}{{(25)}^{2}}] [25 - 10 \times 0.031] = 10 \times 0.0821 \times T T \approx 1539.5 K$

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