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A vessel of volume 10 liters is filled with H₂ gas. The total average translational kinetic energy of its molecules is $4.5 \times 10^{5} J$ . The pressure of hydrogen in the vessel is

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$3 \times 10^{4} {Nm}^{- 2}$

$30 \times 10^{4} {Nm}^{- 2}$

$3 \times 10^{6} {Nm}^{- 2}$

$30 \times 10^{6} {Nm}^{- 2}$

answer is B.

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Detailed Solution

$V = 10 L = 10 \times 10^{- 3} m^{3}$

$P = \frac{2}{3} \frac{E}{V} = \frac{2}{3} (\frac{4.5 \times 10^{5}}{10 \times 10^{- 3}}) = 30 \times 10^{6} N / m^{2}$

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