A vessel of volume ‘V’ is half filled with a liquid A of volume coefficient α1 and other upper half with a liquid B of volume coefficient α2 at 0∘C . If the vessel has negligible coefficient of expansion the mass of liquid that over flows when heated to 5∘C is (Given density of liquid A is d and that of liquid B is 0.8 d)

dA>dB , increase in volume = ΔV=ΔVA+ΔVB=V2α15+V2α25 =V2(α1+α2)5Mass of liquid over flows = Δm=ΔV×dB=V2(α1+α2)5×0.8d =2Vd(α1+α2)

A vessel of volume ‘V’ is half filled with a liquid A of volume coefficient α1 and other upper half with a liquid B of volume coefficient α2 at 0∘C . If the vessel has negligible coefficient of expansion the mass of liquid that over flows when heated to 5∘C is (Given density of liquid A is d and that of liquid B is 0.8 d)

dA>dB , increase in volume = ΔV=ΔVA+ΔVB=V2α15+V2α25 =V2(α1+α2)5Mass of liquid over flows = Δm=ΔV×dB=V2(α1+α2)5×0.8d =2Vd(α1+α2)

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A vessel of volume ‘V’ is half filled with a liquid A of volume coefficient $α_{1}$ and other upper half with a liquid B of volume coefficient $α_{2}$ at $0^{\circ} C$ . If the vessel has negligible coefficient of expansion the mass of liquid that over flows when heated to $5^{\circ} C$ is
(Given density of liquid A is d and that of liquid B is 0.8 d)

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$V d (α_{1} + α_{2})$

$2 V d (α_{1} + α_{2})$

$5 V d (\frac{α_{1} + α_{2}}{2})$

$2 V d (α_{1} - α_{2})$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$d_{A} > d_{B}$ , increase in volume = $Δ V = Δ V_{A} + Δ V_{B}$

$= \frac{V}{2} α_{1} 5 + \frac{V}{2} α_{2} 5 = \frac{V}{2} (α_{1} + α_{2}) 5$

Mass of liquid over flows = $Δ m = Δ V \times d_{B}$

$= \frac{V}{2} (α_{1} + α_{2}) 5 \times 0.8 d = 2 V d (α_{1} + α_{2})$

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!