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Q.

A voltmeter of 250 mV range having a resistance of  9Ω is converted into an ammeter of 250mA range.  The value of necessary shunt is

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a

2Ω

b

10Ω

c

0.1Ω

d

1Ω

answer is C.

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Detailed Solution

i=VR=25010=25mA

We know  ig=[SG+S]i

⇒            25=[S9+S]250

⇒            9S=9⇒S=1Ω

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A voltmeter of 250 mV range having a resistance of  9Ω is converted into an ammeter of 250mA range.  The value of necessary shunt is