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Q.

A wall has two layers A and B, each made of a different material. Both the layers have the same thickness. The thermal conductivity of the material of ‘A’ is twice that of B. If under thermal equilibrium the temperature difference across the wall is 36oC  then the temperature difference across the layer ‘A’ is

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a

6^circ C

b

12^circ C

c

18^circ C

d

24^circ C

answer is B.

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Detailed Solution

Given,,{T_1} - {T_3} = 36

Question Image

frac{{2kA({T_1} - {T_2})}}{x} = frac{{kA({T_2} - {T_3})}}{x}

2({T_1} - {T_2}) = ({T_2} - {T_3})

= 36 - ({T_1} - {T_2})

therefore {T_1} - {T_2} = 12^circ C

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