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Q.

A watch which gains uniformly was observed to be 6 minutes slow at 8.00 am on a day. At 6.00 p.m on the same day it was 1 minute fast. At what time did the watch show the correct time

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a

4 : 40 PM

b

4 : 30 PM 

c

4 : 34 PM

d

4 : 48 PM

answer is C.

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Detailed Solution

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6×107=8 hr 34 min  =  4.34  PM

8:00 Am+8 hr 34 min=4.34pm

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