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Q.

A water drop of radius 1 cm is broken into 729 equal droplets. If surface tension of water is 75 dyne/cm, then the gain in surface energy upto first decimal place will be :
(Given π=3.14)

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An Intiative by Sri Chaitanya

a

8.2×10−4J

b

8.5×10−4J

c

7.5×10−4J

d

5.3×10−4J

answer is C.

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Detailed Solution

729×43πr3=43πR3⇒R=9r⇒r=R9=19cmΔU=S×ΔA⇒ΔU=S×−4πR2+729×4πr2=S×4π729r2−81r2=7.5×10−4J

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