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A water drop of radius 1 mm is sprayed into $10^{6}$ droplets of the same size at constant temperature. If surface tension of water is $72 \times 10^{- 3}$ N/m, then the work done is

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$8.95 \times 10^{- 5} e r g$

$8.95 \times 10^{- 5} J$

$17.90 \times 10^{- 5} J$

$17.90 \times 10^{- 5} e r g$

answer is B.

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Detailed Solution

$W = T 4 π R^{2} (n^{1 / 3} - 1)$

$\begin{array}{l} = 72 \times 10^{- 3} \times 4 \times π \times {(10^{- 3})}^{2} [100 - 1] \\ = 8.95 \times 10^{- 5} J \end{array}$

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