Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A water drop of radius 1μm falls in a situation where the effect of buoyant force is negligible. Coefficient of viscosity of air is 1.8×105 Nsm2 and its density is negligible as compared to that of water i.e, 106 gm-3. Terminal velocity of the water drop is:  (take acceleration due to gravity =10ms-2 )

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

145.4×106ms1

b

118.0×106ms1

c

123.4×106ms1

d

132.6×106ms1

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

We know that terminal velocity is given by Vr=2gr29ηρρt
Here, we have no involvement of buoyant force. So remove ρt
Then, Vr=2gr2ρ9η=2×10×1012×1039×1.8×105=123.4×106m/s

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring