Q.

A water heater of power 2000 W is used to heat water. The specific heat capacity of water is 4200 J kg-1 K-1. The efficiency of heater is 70%. Time required to heat 2 kg of water from 10° C to  60°C is ____s. (Assume that the specific heat capacity of water remains constant over the temperature range of the water)

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answer is 300.

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Detailed Solution

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Given power = 2000W and efficiency = 70%

Heat required to increase the temperature of water by T is

Heat = msT

Therefore,

70100P=msΔTt

70100(2000)=2×4200×50t

t=2×4200×5070×20=300sec

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