A water sample has ppm level concentration of following anions $F^{-} = 10; {SO}_{4}^{2 -} = 100; {NO}_{3}^{-} = 50$ the anion/ anions that make/ makes the water sample unsuitable for drinking is/are:

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only ${NO}_{3}^{-}$

both ${SO}_{4}^{2 -}$ and ${NO}_{3}^{-}$

only $F^{-}$

only ${SO}_{4}^{2 -}$

answer is C.

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Detailed Solution

The anions are fluorine $F^{-}$ , sulphate ${SO}_{4}^{2 -}$ , and nitrate ${NO}_{3}^{-}$ .
Fluorine ions with ppm values of 10, sulphate ions with ppm values of 100, and nitrate ions with ppm values of 50 are present in the provided water sample.
The amount of nitrate ion that can be present in drinking water is limited at 50 ppm. Methemoglobinemia, or "blue baby syndrome," is caused when the maximum allowable level of nitrate ion in drinking water is exceeded.
The World Health Organization (WHO) has set a 500 ppm sulphate ion maximum limit. When the sulphate ion concentration in drinking water is too high, it has a laxative effect.
The fluorine ion's maximal concentration is 1.5 ppm, and the higher.