A wave travelling in positive X-direction with A = 0.2 m has a velocity of 360 m/sec if $\lambda$ = 60 m, then correct expression for the wave is

A wave travelling in positive x-direction may be represented as $\mathrm{y} = \mathrm{Asin}\left[\mathrm{V}(\omega \mathrm{t}-\mathrm{x})\right]$.

On putting values $\mathrm{y} = 0.2\sin \frac{2\mathrm{\pi }}{60}(360\mathrm{t}-\mathrm{x})$

$\Rightarrow y = 0.2 \sin 2\mathrm{\pi }(6\mathrm{t}-\frac{\mathrm{x}}{60})$