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A wax candle floats vertically in a liquid of density twice that of wax. The candle burns at the rate of $4 c m / h r .$ Then, with respect to the surface of the liquid the upper end of the candle will

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remain at the same height

rise at the rate of 2cm/hr

fall at the rate of 2cm/hr

fall at the rate of 4cm/hr

answer is B.

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Detailed Solution

$V_{i n} ρ_{w a t e r} g = V ρ_{w a x} g, V_{o u t} = \frac{V}{2}, A h = \frac{A L}{2}, \frac{d h}{d t} = \frac{1}{2} \frac{d L}{d t} = 2 c m / h r$

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