Q.

A weak acid HA has degree of dissociation x.  Thus, pHpKa is 

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a

p1x

b

p1x+px

c

px

d

p1xpx

answer is D.

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Detailed Solution

                           HAH++A Initial                    C       0       0 After ionisation C-Cx  ?    Cx

Ka=H+A[HA] H+=Ka[HA]A=KaC(1x)Cx=Ka1xx logH+=logKa+log(1x)logx logH+=logKalog(1x)(logx) pH=pKa+p(1x)px pHpKa=p1xpx

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A weak acid HA has degree of dissociation x.  Thus, pH−pKa is