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A weak acid HX has the dissociation constant $1 \times 10^{- 5} M$ It forms a salt $NaX$ on reaction with alkali. The percentage hydrolysis of 0.1 M solution of $NaX$ is:

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0.0001 %

0.01 %

0.15%

0.1 %

answer is B.

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Detailed Solution

Hydrolysis of $NaX,$

$h = \sqrt{\frac{K_{w}}{K_{a} \times C}} h = \sqrt{\frac{10^{- 14}}{10^{- 5} \times 0.1}} = 10^{- 4}$

So, the percentage of hydrolysis,

$= 10^{- 4} \times 100 = 0.01 %$

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