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A weak electrolyte having the limiting equivalent conductance of 400 S cm². equivalent^–1 at 298 K is 2% ionized in its 0.1 N solution.
The resistance of this solution (in ohms) in an electrolytic cell of cell constant 0.4 cm^–1 at this temperature is

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200

300

400

500

answer is D.

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Detailed Solution

$\land_{C} = \land_{0} \times α = 400 \times \frac{2}{100} = 8$

$\land_{C} = \frac{1}{R} \times \frac{l}{A} \times \frac{1000}{N} \Rightarrow R = \frac{1000}{\land_{C} \times N} \times (\frac{l}{A})$

$\Rightarrow R = \frac{0.4 \times 1000}{8 \times 0.1} = 500 o h m s$

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