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A weighted glass tube floats in a liquid with length l of the tube immersed in the liquid. It is pushed down through a certain distance y and released. The frequency of oscillations will be

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$2 π \sqrt{(g / l)}$

$\frac{1}{2 π} \sqrt{(l / g)}$

$\frac{1}{2 π} \sqrt{(g / l)}$

$\frac{1}{2 π} \sqrt{(g / y)}$

answer is C.

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Detailed Solution

$Restoring force = A y ρg$

$acceleraion = \frac{Ayρg}{Alρ} = \frac{gy}{l}$

$T = \frac{2 π}{\sqrt{(\frac{g}{l})}}$

$or n = \frac{1}{2 π} \sqrt{(\frac{g}{l})}$

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