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A weightless rod is acted upon by two upward parallel forces of 2 N and 4 N at ends A and B respectively. The total length of the rod AB = 3 m. To keep the rod in equilibrium a force of 6 N should act in the following manner.

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Downwards at a point D such that BD = 1 m

Downwards at any point between A and B

Downwards at the mid point of AB

Downwards at a point C such that AC = 1 m

answer is D.

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Detailed Solution

$2 (3 - x) = 4 x \Rightarrow x = 1 m$

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