A what height from the surface of earth the gravitation potential and the value of g are -5.4×107 J/kg2 and 6.0 m/s2 respectively? Take the radius of earth as 6400km :

V=-GMR+h=-5.4×107 ......(1)and g=GM(R+h)2=6 ......(2)Dividing (1) by (2), we get⇒ R+h=5.4×1076 ⇒ R+h=9000 km ∴ h=2600 km

A what height from the surface of earth the gravitation potential and the value of g are -5.4×107 J/kg2 and 6.0 m/s2 respectively? Take the radius of earth as 6400km :

V=-GMR+h=-5.4×107 ......(1)and g=GM(R+h)2=6 ......(2)Dividing (1) by (2), we get⇒ R+h=5.4×1076 ⇒ R+h=9000 km ∴ h=2600 km

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A what height from the surface of earth the gravitation potential and the value of $g$ are $- 5.4 \times 10^{7} J / k g^{2}$ and $6.0 m / s^{2}$ respectively? Take the radius of earth as $6400 k m$ :

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$1600 k m$

$2600 k m$

$1400 k m$

$2000 k m$

answer is B.

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$V = - \frac{G M}{R + h} = - 5.4 \times 10^{7} . . . . . . (1)$

and $g = \frac{G M}{{(R + h)}^{2}} = 6 . . . . . . (2)$

Dividing $(1)$ by $(2)$ , we get

$\Rightarrow R + h = \frac{5.4 \times 10^{7}}{6} \Rightarrow R + h = 9000 k m ∴ h = 2600 k m$

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A what height from the surface of earth the gravitation potential and the value of g are -5.4×107 J/kg2 and 6.0 m/s2 respectively? Take the radius of earth as 6400km :

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A what height from the surface of earth the gravitation potential and the value of $g$ are $- 5.4 \times 10^{7} J / k g^{2}$ and $6.0 m / s^{2}$ respectively? Take the radius of earth as $6400 k m$ :