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A wheel has an angular acceleration of 3.0 rad/s² and an initial angular speed of 2.00 rad/s. In a time of 2 s it has rotated through an angle(in radian) of

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answer is B.

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Detailed Solution

Given, $α = 3.0 rad / s^{2}, ω_{0} = 2.0 rad / s, t = 2 s$

We have $θ = ω_{o} t + \frac{1}{2} α t^{2}$

Hence, $θ = 2 \times 2 + \frac{1}{2} \times 3 \times {(2)}^{2}$

or $θ = 4 + 6 = 10 rad$

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