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A wheel of diameter ‘d’ is rolling without slipping with speed v on a horizontal road. When it is at point ‘A’ on the road a small lump of mud separates from the wheel at its highest point ‘B’ and drops at point ‘C’ on the road . The distance ‘AC’ will be $v \sqrt{\frac{x d}{g}}$ then $x =______$

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answer is 8.

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Detailed Solution

$\begin{array}{l} A C = (2 V) t \\ = (2 V) \sqrt{\frac{2 d}{g}} \\ = V \sqrt{\frac{8 d}{g}} \end{array}$

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