Q.

A wheel of radius 0.4 m can rotated freely about its axis as shown in the figure. A string is wrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad-s-2 is produced in it due to the torque. Then moment inertia of the wheel is (g = 10ms-2)

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a

1 kg - m2

b

1.36 kg - m2

c

2 kg - m2

d

8 kg - m2

answer is A.

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Detailed Solution

Given,

 R=0.4m , α=8rad/s2 , M=4kg

We know that ,

Torque=r×f

I×α=R×F 

I×8=0.4×mg 

I×8=0.4×10×4

I=410×10×8×4=2kg/m2

Hence the correct answer is 2kg-m2.

 

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