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Q.

A wheel of radius R is free to rotate about its natural axis and I is its moment of inertia If a tangential force F is applied on the wheel along its rim then angular acceleration is

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a

FIR

b

$\frac{FR}{I}$

c

$\frac{I F}{R}$

d

$\frac{I R}{F}$

answer is B.

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Detailed Solution

Torque $τ = \vec{R} \times \vec{F} = R \times F ∵ \vec{R} ⊥ \vec{F}$

$τ = I α,$

$I α = RF$

$α = \frac{RF}{I}$

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