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Q.

A wheel of radius R rolls on the ground with a uniform velocity v. The relative acceleration of top most point of the wheel with respect to the bottom most point is

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a

$\frac{V^{2}}{R}$

b

$\frac{2 V^{2}}{R}$

c

$\frac{V^{2}}{2 R}$

d

$\frac{4 V^{2}}{R}$

answer is B.

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Detailed Solution

Question Image

v_r = v_PQ = 2v,
$∴ a_{r} = \frac{{v_{r}}^{2}}{2 R} = \frac{4 v^{2}}{2 R} = \frac{2 v^{2}}{R}$

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