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Q.

A wheel of radius ‘r’ rolls without slipping with a speed ‘v’ on a horizontal road. When it is at point ‘A’ on the road, a small lump of mud separates from the wheel at its highest point B and drops at point ‘C’ on the road. The distance AC will be

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a

4vrg

b

2vrg

c

v3rg

d

vrg

answer is C.

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Detailed Solution

Question Image

Horizontal velocity of the lump of mud will be 

VB= V+Rω=2V

R = (horizontal velocity)x(time of flight)

=(2V)2hg=2V2(2r)g⇒R=4Vrg

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