A wheel of radius ‘r’ rolls without slipping with a speed ‘v’ on a horizontal road. When it is at point ‘A’ on the road, a small lump of mud separates from the wheel at its highest point B and drops at point ‘C’ on the road. The distance $AC = nv \sqrt{\frac{r}{g}}$ Find ‘n’

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Detailed Solution

It is similar to horizontal projection from the top of power of height 2r Range Question Image

Range =Velocity x time
$= (2 v) \sqrt{\frac{2 h}{g}} = (2 v) \sqrt{\frac{2 \times 2 r}{g}}$

$The Distance AC = 4 v \sqrt{\frac{r}{g}}$

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