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A wheel, starting from rest, rotates with a uniform angular acceleration of 2 rad $s^{- 2}$ . Then the number of rotations it performs in tenth second is

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answer is A.

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Detailed Solution

$ω_{0} = 0 (S_{n} = u + \frac{1}{2} a (2 n - 1))$ $θ_{10} = \frac{α}{2} (2 n - 1) = \frac{2}{2} (2 \times 10 - 1) = 19 r a d$
Number of revolutions: $\frac{19}{2 π} = 3$

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