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A whistle with frequency 1020 Hz is blown at a station. A man travelling in train moving towards the station at 30 ms^-1 hears the sound of the whistle. If the speed of sound is 340 ms^-1, the apparent frequency heard by him is

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1020 Hz

1110 Hz

2040 Hz

610 Hz

answer is B.

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Detailed Solution

Apparentt frequency $n' = n (\frac{v + v_{0}}{v})$

$\Rightarrow n' = 1020 (\frac{340 + 30}{340})$

$\Rightarrow n' = 1020 \times 1.088 \Rightarrow n' = 1110 Hz$

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