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Q.

A wind with speed 40 m/s blows parallel to the roof of a house. The area of the roof is $250 m^{2}$ . Assuming that the pressure inside the house is atmospheric pressure, the force exerted by the wind on the roof and the direction of the force will be $(d_{a i r} = 1.2 k g / m^{3})$

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a

$4.8 \times 10^{5} N,$ downwards

b

$2.4 \times 10^{5} N,$ downwards

c

$2.4 \times 10^{5} N,$ upwards

d

$4.8 \times 10^{5} N,$ upwards

answer is C.

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Detailed Solution

$(P_{1} - P_{2}) A = \frac{1}{2} ρ (V_{2}^{2} - V_{1}^{2}) A$

$= \frac{1}{2} \times 1.2 (40^{2}) \times 250 N$

$= 2.4 \times 10^{5} N, upward$

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A wind with speed 40 m/s blows parallel to the roof of a house. The area of the roof is 250 m2. Assuming that the pressure inside the house is atmospheric pressure, the force exerted by the wind on the roof and the direction of the force will be (dair=1.2 kg/m3)