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A winding wire which is used to frame a solenoid can bear a maximum 10 A current. If length of solenoid is 80 cm and its cross sectional radius is 3 cm then required length of winding wire is (B = 0.2 T)

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1.2x10² m

4.8x10² m

2.4x10³ m

6x10³ m

answer is C.

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Detailed Solution

where N = Total number of turns, l = length of the solenoid

\Rightarrow 0.2 = \frac{{4\pi \times {{10}^{ - 7}} \times N \times 10}}{{0.8}} \Rightarrow N = \frac{{4 \times {{10}^4}}}{\pi }

Since N turns are made from the winding wire so length of the wire (L)

[

length of each turns]

\Rightarrow L = 2\pi \times 3 \times {10^{ - 2}} \times \frac{{4 \times {{10}^4}}}{\pi } = 2.4 \times {10^3}m

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