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A window fitted with a wire mesh and distant 200m is being viewed with the help of a telescope. The spacing between the wires of the mesh is 2 mm. The wavelength of light used is 5000 $\overset{0}{A}$ . The minimum diameter of the telescope will be --

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5.9 cm

6.1 cm

4.2 cm

3.6 cm

answer is A.

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Detailed Solution

$\begin{array}{l} \frac{1 .22 λ}{a} = \frac{r}{f}; a = \frac{(1 .22) (5 \times 10^{- 7}) (200)}{2 \times 10^{- 3}} \\ = 610 \times 10^{4} m = 6 .1 cm \end{array}$

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