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Q.

A wire 50 cm long and 1 mm2 in cross-section carries a current of 4 A when connected to a 2 V battery. The resistivity of the wire is

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a

2x10-7

b

5x10-7

c

1x10-6

d

4x10-6

answer is C.

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Detailed Solution

Resistance can be calculated using Ohm's law from current and voltage, as shown below.
R =

\frac{V}{I}

=

\frac{2}{4}

=

\frac{1}{2}

Ω
The resistance R is determined by resistivity, length, and cross-section area, as shown below.
R = ρ

\frac{l}{A}

\frac{1}{2}

= ρ

\frac{0.50}{10^{- 6}}

This implies the resistivity of the wire is 10-6

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