A wire ‘A’ of finite length carrying current $I_1$  is kept on right side of a long current carrying wire.  If the force on the wire A is F and torque on it is T, then  

$F=downward$         $F.L.H.R$

$F.L.H.R$                     $B\alpha \frac{1}{\gamma }$

$B_1>B_2$              $F_1>F_2$

$Torque=Anticlockwise$

$\text{ Usmg ampere's right hand thumb rule and }$$\text{ from F.L.H rule }\mathrm{F}\text{ downwards and }\mathrm{T}\text{ is ACW }$