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Q.

A wire frame ABCDEF is kept as shown in figure I is the current in the wire frame. 

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a

The direction of magnetic field at Q (a,0,0) due to wire EF and CD will be along ( -j^ )

b

The direction of magnetic field at P (O,a,0) due to wire CD and EF will be along ( -j^ ) 

c

The direction of magnetic field at P(O,a,0) due to wire AF and CB will be along ( -i^ ) 

d

The direction of magnetic field at 'O' due to the wire frame will be along i^j^2

answer is A, B, C, D.

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Detailed Solution

Direction of magnetic field at P due to CD=i^×(j^+k^)2=k^j^2

Direction of magnetic field at P due to EF=i^×(j^k^)2=-k^j^2

Hence direction of magnetic field at P due to CD and EF will be along -j^.

Direction of magnetic field at 'O' due to upper frame along -i^

Direction of magnetic field at O due to horizontal frame will be along -j^.

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