A wire is cut into several small pieces. Each of the small pieces is bent into a square of 2cm. If the total area of the small squares is 28 square cm, then the original length of the wire was of ____.

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Detailed Solution

A wire is cut into several small pieces. Each of the small pieces is bent into a square of 2cm. If the total area of the small squares is 28 square cm, then the original length of the wire was 56 cm.
Given that,
Length of the square = 28 sq.cm and total area of the small squares is 28 sq.cm.
Number of small squares,
=

\frac{Total area of small squares}{Area of one small squares}

\frac{28}{2 \times 2}

= 7
Perimeter of small squares = 4

\times

side
= 4

\times

2
= 8
Perimeter of the small square is 8 cm.
Perimeter of 7 such small squares = 7

\times

Perimeter of a small square
= 7

\times

8
= 56
Perimeter of 7 such small squares is 56 sq.cm.
Original length of the wire = Perimeter of 7 small square = 56.
Hence, the original length of wire is 56 cm.

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