Q.

A wire is suspended from the ceiling and stretched under the action of a weight F suspended from its other end. The force exerted by the ceiling on it is equal and opposite to the weight. 

a) Tensile stress at any cross section A of the wire is F/A. 

b Tensile stress at any cross section is zero. 

c) Tensile stress at any cross section A of the wire is 2F/A. 

d) Tension at any cross section A of the wire is F.

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

Only a & d are true

b

Only b 

c

Both a & c

d

All are correct

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

solution

From the figure,

Stress=forcearea=FA

The force applied to a wire when it is suspended from the ceiling and stretched by a weight (F) suspended from its other end is equal to and in the opposite direction of the force applied by the weight. 

The tension, however, is merely F and not 2F at any cross-section A of the wire. As a result, the tension per unit area, or tensile stress, is equal to F/A.

Hence the correct answer is only a & d are true.

Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon