A wire loop formed by joining two semi – circular wires of radii a1 and a2 carries a current i as shown in the adjoining figure. The magnetic induction at the centre O is

B=B1−B2=μ0i4a1−μ0i4a2B=μ0i41a1-1a2

A wire loop formed by joining two semi – circular wires of radii a1 and a2 carries a current i as shown in the adjoining figure. The magnetic induction at the centre O is

B=B1−B2=μ0i4a1−μ0i4a2B=μ0i41a1-1a2

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A wire loop formed by joining two semi – circular wires of radii a₁ and a₂ carries a current i as shown in the adjoining figure. The magnetic induction at the centre O is

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$\frac{μ_{0} i}{4} (\frac{1}{a_{1}} + \frac{1}{a_{2}})$

$\frac{μ_{0} i}{4} (\frac{1}{a_{1}} - \frac{1}{a_{2}})$

$\frac{μ_{0} i}{2} (\frac{1}{a_{1}} + \frac{1}{a_{2}})$

$\frac{μ_{0} i}{2} (\frac{1}{a_{1}} - \frac{1}{a_{2}})$

answer is B.

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$B = B_{1} - B_{2} = \frac{μ_{0} i}{4 a_{1}} - \frac{μ_{0} i}{4 a_{2}}$

$B = \frac{μ_{0} i}{4} (\frac{1}{a_{1}} - \frac{1}{a_{2}})$

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A wire loop formed by joining two semi – circular wires of radii a1 and a2 carries a current i as shown in the adjoining figure. The magnetic induction at the centre O is

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A wire loop formed by joining two semi – circular wires of radii a₁ and a₂ carries a current i as shown in the adjoining figure. The magnetic induction at the centre O is