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Q.

A wire of given material having length l and area of cross-section A has a resistance of 8 Ω. What would be the resistance of another wire of the same material having length l/2 and area of cross-section 2A?

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a

3Ω

b

4Ω

c

1Ω

d

2Ω

answer is B.

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Detailed Solution

For first wire

R1=ρ×IA=8Ω

Now for the second wire

R2=ρ×I/22 A=14×ρ×1 A

R2=14×R1

R2=2Ω

The resistance of the new wire is 2Ω.

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