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Q.

A wire of given material having length l and area of cross-section A has a resistance of 4 Ω. What would be the resistance of another wire of the same material having length l2 and area of cross-section 2A?

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a

8Ω

b

4Ω

c

2Ω

d

1Ω

answer is B.

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Detailed Solution

For first wire, R1=ρlA=4Ω

Now for the second wire, R2=ρl/22A=14R1

R2= 1Ω
The resistance of the new wire is 1Ω.

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