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A wire of length ‘1’ meters , made of material of specific gravity 8 is floating horizontally on the surface of water. If it is not wet by water, the maximum diameter of the wire (in mm) up to which it can continue to float is $\frac{x}{10}$ (surface tension of water is T = 70 x 10^-3Nm^-1 ), Then find x ?

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answer is 15.

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Detailed Solution

$mg = 2 TL \Rightarrow {πr}^{2} Lρg = 2 TL \Rightarrow π \frac{d^{2}}{4} ρg = 2 T \Rightarrow d = \sqrt{\frac{8 T}{πρg}}$
On substitution of values, d =1.5 mm

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