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Q.

A wire of length 10cm is bent into an arc of a circle such that it subtends an angle of 1 radian at the centre. If a current of 1A is passed through the wire, the magnetic induction at the centre of the circle will be

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a

$2 \times 10^{- 4} tesla$

b

$1 \times 10^{- 6} tesla$

c

$2 \times 10^{- 6} tesla$

d

$1 \times 10^{- 4} tesla$

answer is B.

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Detailed Solution

$B = \frac{μ_{0} I}{4 πr} (θ) = \frac{4 π \times 10^{- 7} \times 1}{4 π (\frac{l}{θ})} = \frac{10^{- 7} \times 1}{10^{- 1}} = 10^{- 6} T$

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