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Q.

A wire of length 1m and radius 1mm is subjected to a load. The extension is ‘x’. The wire is melted and then drawn into a wire of square cross – section of side 1mm. What is its extension under the same load?

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a

π2x

b

πx

c

π/x

d

πx2

answer is A.

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Detailed Solution

Equating volume A1ℓ1=A2ℓ2 

πr2l1=a2l2

π×10−32×1=10−32ℓ2

ℓ2=π

e=FℓAy⇒e1e2=ℓ1ℓ2A2A1

xe2=1π×10−6π×10−32

e2=π2x

 

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