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Q.

A wire of length 4 m and radius 0.25 mm has a resistance of 24 Ω . The resistivity of material of wire is

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a

1.1775×10−6 Ωm

b

1775×10−6 Ω cm

c

17.75×10−6 Ωm

d

1885×10−6 Ω cm

answer is A.

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Detailed Solution

ρ=RAl=24×π(0.25×10−3)24=1.1775×10−6Ωm
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