A wire of length 40 m is bent to form a square. What is the area of the square thus formed?

The length of the wire = 40 m

The wire is bent to form a square. Therefore, the length of the wire is equal to the perimeter of the square thus formed.

∴ The perimeter of the square = 40 m

Hence, 4 × Side = 40 m

$\Rightarrow \mathrm{Side}=\frac{40}{4}=10 \mathrm{m}$

∴ The area of the square = side × side = 10 m × 10 m = 100 sq m

Therefore, the area of the square thus formed is 100 sq m.