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A wire of length ‘L’ and radius ‘r’ is clamped rigidly at one end. When the other end of the wire is pulled by a force f, its length increases by l. Another wire of same material of length '2L' and radius '2r ' is pulled by a force '2f '. Then the increase in its length will be:

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l/2

answer is B.

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Detailed Solution

For a given material, Y = constant

$\Rightarrow \frac{fL}{{πr}^{2} l} = \frac{2 f \times 2 L}{π (4 r^{2}) e_{2}}$

$\Rightarrow e_{2} = l$

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